9+49=x^2+6x+9

Solution for 9+49=x^2+6x+9 equation:

9+49=x^2+6x+9

We move all terms to the left:

9+49-(x^2+6x+9)=0

We add all the numbers together, and all the variables

-(x^2+6x+9)+58=0

We get rid of parentheses

-x^2-6x-9+58=0

We add all the numbers together, and all the variables

-1x^2-6x+49=0

a = -1; b = -6; c = +49;
Δ = b2-4ac
Δ = -62-4·(-1)·49
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{58}}{2*-1}=\frac{6-2\sqrt{58}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{58}}{2*-1}=\frac{6+2\sqrt{58}}{-2}
$